-32x^2+210x+8=0

Solution for -32x^2+210x+8=0 equation:

-32x^2+210x+8=0

a = -32; b = 210; c = +8;
Δ = b2-4ac
Δ = 2102-4·(-32)·8
Δ = 45124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45124}=\sqrt{4*11281}=\sqrt{4}*\sqrt{11281}=2\sqrt{11281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(210)-2\sqrt{11281}}{2*-32}=\frac{-210-2\sqrt{11281}}{-64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(210)+2\sqrt{11281}}{2*-32}=\frac{-210+2\sqrt{11281}}{-64}
$